When the terminals of a cell are connected by a wire of resistance 4 , the potential difference across the cell is 1.6 V . If a wire of the same resistance is connected in parallel with the first, the potential difference becomes 1.33 ~V .

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When the terminals of a cell are connected by a wire of resistance 4 , the potential difference across the cell is 1.6 V . If a wire of the same resistance is connected in parallel with the first, the potential difference becomes 1.33 ~V . The emf and internal resistance of the cell are respectively

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Correct answer: B. 2 ~V , 1

E=V+I r Given, V=1.6 ~V ; R=4 I₁= 1.6 4 =0.4 ~A When a resistance of 4 is connected in parallel the resultant resistance 1 R^ = 1 4 + 1 4 = 2 4 R^ =2 I₂= 133 2 =0.66 ~A From Eqs. (i) and (i i) , we get aligned & 1.6+0.4 r=1.33+0.66 r & r= 0.27 0.26 =1 aligned Substituting of r in Eq. (i), we get E=1.6+0.4 1=2 ~V

When the terminals of a cell are connected by a wire of resistance 4 , the potential difference across the cell is 1.6 V . If a wire of the same resistance is connected in parallel with the first, the potential difference becomes 1.33 ~V . The emf and internal resistance of the cell are respectively

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