In a meter bridge experiment, when a nichrome wire is in the right gap, the balancing length is 60 ~cm . When the nichrome wire is uniformly stretched to increase its length by 20 % and again connected in the right gap, the new balancing length is nearly

Step-by-step solution

Since R l aligned & R_L R_R = 60 100-60 = 60 40 = 6 4 = 3 2 ... (i) & R_L 144 R_R = l 100-l ... (ii) aligned From eqs. (i) and (ii) aligned & 144 R_R R_R = 3 / 2 l / 100-l = 3 2 100-l l & 100-l l = 2 3 144=2 0.48=0.96 & 100-i=0.96 l aligned or, 1.96 l=100 or, l= 100 196 =51.02 ~cm =51 ~cm