AP EAMCET2006PhysicsCurrent Electricity
One end each of a resistance r capacitor C and resistance 2 r are connected together. The other ends are respectively connected to the positive terminals of batteries, P, Q, R having respectively emf's E, E and 2 E . The negative terminals of the batteries are then connected together. In this circuit, with steady current the potential drop across the capacitor is :
Options
- AE 3
- BE 2
- C2 E 3
- DE
Correct answer
A. E 3
Step-by-step solution
In the steady state, no current flows through capacitor branch. Current in the circuit i= net emf net resistance = 2 E-E r+2 r = E 3 r So, potential drop across capacitor V=i r= E 3 r r= E 3