A 6 ~V cell with 0.5 internal resistance, a 10 ~V cell with 1 internal resistance and a 12 external resistance are connected in parallel. The current (in ampere) through the 10 ~V cell is

Step-by-step solution

In closed loop A B G F E H A , aligned 10-i₂ 1+i₁ 0.5-6 & =0 0.5 i₁-i₂ & =-4 aligned In closed loop B C D E B , array r (i₁+i₂ ) 12+i₂ 1-10=0 12 i₁+13 i₂=10 array From Eqs. (i) and (ii), we get i₂=2.87 ~A