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AP EAMCET2004PhysicsCurrent Electricity

Two cells A and. B are connected in the secondary circuit of a potentiometer one at a time and the balancing length are respectively 400 ~cm and 440 ~cm . The emf of the cell A is 1.08 volt. The emf of the second cell B in volts is

Options

  1. A1.08
  2. B1.188
  3. C11.88
  4. D12.8

Correct answer

B. 1.188

Step-by-step solution

array lc E₁ E₂ = l₁ l₂ & & 1.08 E₂ = 400 440 & E₂= 440 1.08 400 =1.188 ~V array

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