AP EAMCET202421 May 2024Evening ShiftPhysicsElectromagnetic InductionActual
The current passing through a coil of 120 turns and inductance. 40 mH is 30 mA . The magnetic flux linked with the coil is
Options
- A20 10⁻⁶ ~Wb
- B5 10⁻⁶ ~Wb
- C12 10⁻⁶ ~Wb
- D10 10⁻⁶ ~Wb
Correct answer
D. 10 10⁻⁶ ~Wb
Step-by-step solution
N =120, ~L =40 mH , I =30 ~mA The magnetic flux linked with the coil is = LI ~N = 40 10⁻³ 30 10⁻³ 120 =10 10⁻⁶ ~Wb