AP EAMCET20228 Jul 2022Morning ShiftPhysicsElectromagnetic InductionActual
A circular coil of area 0.01 ~m ^2 and 40 turns is rotated about its vertical diameter with an angular speed of 50 rad s ⁻¹ in a uniform horizontal magnetic field 0.05 ~T . If the average power loss due to joule heating is 25 ~mW , then the closed loop resistance of the coil is
Options
- A50
- B12.5
- C75
- D20
Correct answer
D. 20
Step-by-step solution
We have aligned & e = d dt = NBA d dt ( t ) & = NBA t aligned aligned & e _ = NBA & e _ rms = NBA 2 aligned aligned & P_ avg = e _ rms ^2 R R = e _ rms ^2 P _ avg = N ^2 ~B ^2 ~A ^2 ^2 2 P _ avg & = 40^2 0.05^2 0.01^2 50^2 2 25 10⁻³ & =20 aligned