A solenoid has the length 1 ~m and the area of cross-section 0.02 ~m ^2 . If number of turns in the solenoid is 5 0 0 0 then the self inductance of the solenoid is

Step-by-step solution

For a solenoid, coefficient of self induction is given by L= ₀ N^2 A l Here, Number of turns, N=5000 , length., l=1 ~m , Area, A=0.02 ~m ^2 Also ₀=4 10⁻⁷ Tm / A So, self inductance of solenoid is L= 4 10⁻⁷ (5000)^2 0.02 1 =0.2 H