A uniform magnetic field B is perpendicular to the plane of a circular loop of diameter 10 ~cm formed from wire of diameter 2 ~mm and resistivity 2 10⁻⁸ m . If a current of 11 ~A is to be induced in the loop then the rate at which B is to b

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A uniform magnetic field B is perpendicular to the plane of a circular loop of diameter 10 ~cm formed from wire of diameter 2 ~mm and resistivity 2 10⁻⁸ m . If a current of 11 ~A is to be induced in the loop then the rate at which B is to be changed is

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Correct answer: A. 2.8 Ts ⁻

i = e R = 1 R d dt = A R dB dt Now, A= area of loop = (0.05)^2 =25 10⁻⁴ ~m ^2 R = l Area of cross - section aligned & = 2 10⁻⁸ 2 (0.05) (10⁻³ )^2 [ 1=2 r ] & = 4 0.05 10⁻⁸ 10⁻⁶ & =4 0.05 10⁻² & =2 10⁻³ aligned So, dB dt = iR A = 11 2 10⁻³ 25 10⁻⁴ =2.8 ~T / s

A uniform magnetic field B is perpendicular to the plane of a circular loop of diameter 10 ~cm formed from wire of diameter 2 ~mm and resistivity 2 10⁻⁸ m . If a current of 11 ~A is to be induced in the loop then the rate at which B is to be changed is

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