AP EAMCET202124 Aug 2021Morning ShiftPhysicsElectromagnetic InductionActual
The initial rate of increase of current when a battery of emf 6 ~V is connected in series with an inductance of 2 H and resistance of 12 is
Options
- A0.5 ~A ~s ⁻¹
- B1 ~A ~s ⁻¹
- C3 ~A ~s ⁻¹
- D4 ~A ~s ⁻¹
Correct answer
C. 3 ~A ~s ⁻¹
Step-by-step solution
Given that, emf of battery, E=6 ~V Resistance, R=12 Inductance, L=2 H We know that, the instantaneous current in the circuit containing R and L in series with battery of emf E is I=I₀ (1-e^ -R L t ) where, maximum current at steady state I₀=E / R I= E R (1-e^ -R L t ) Now, the rate of increase of current, d I d t = E R [0- ( -R L ) e^ -R L t ]= E L e^ -R L t At (t=0) initial condition, . d I d t |_ t=0 = E L e^0= E L = 6 2 =3 ~A / s