AP EAMCET202022 Sep 2020Evening ShiftPhysicsElectromagnetic InductionActual
A rod of length 1.0 ~m is rotated in a plane perpendicular to a uniform magnetic field of induction 0.25 ~T with a frequency of 12 rev / s . The induced emf across the ends to the rod is
Options
- A18.89 ~V
- B3 ~V
- C15 ~V
- D9.42 ~V
Correct answer
D. 9.42 ~V
Step-by-step solution
Length of rod, l=1.0 ~m aligned B=0.25 ~T , f & =12 rev / s Induced emf, e & = B l^2 2 = 0.25 2 f 2 1^2 & =0.25 f=0.25 12 & =3 =9.42 ~V aligned