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AP EAMCET201921 Apr 2019Morning ShiftPhysicsElectromagnetic InductionActual

A metal rod A B of length 50 ~cm is moving at a velocity 8 ~ms ⁻¹ in a magnetic field of 2 ~T . If the field is at 60^ with the plane of motion as shown in the figure, then the potentials V_A and V_B are related by

Options

  1. AV_A-V_B=8 ~V
  2. BV_A-V_B=4 ~V
  3. CV_B-V_A=8 ~V
  4. DV_B-V_A=4 ~V

Correct answer

B. V_A-V_B=4 ~V

Step-by-step solution

A metal rod A B shown in the figure moves with speed 8 ~ms ⁻¹ . As the emf induced in the metal rod, aligned e_ A B & =V_A-V_B=l ( V B ) But, V_A-V_B & =l v B (90^ -60^ ) V_A-V_B & =50 10⁻² 8 2 30^ & =8 1 2 =4 ~V aligned Hence, the correct option is (b).

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