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AP EAMCET201823 Apr 2018Evening ShiftPhysicsElectromagnetic InductionActual

A coil of wire of radius r has 600 turns and self inductance of 108 mH . The self inductance of a coil with same radius and 500 turns is

Options

  1. A80 mH
  2. B75 mH
  3. C108 mH
  4. D90 mH

Correct answer

D. 90 mH

Step-by-step solution

Self-inductance of a coil = N _B I = N ₀ I 2 R R^2 I = ₀ 2 N R So, aligned & L₂ L₁ = N₂ N₁ & L₂=L₁ N₂ N₁ =108 500 600 =90 mH aligned

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