AP EAMCET201822 Apr 2018Morning ShiftPhysicsElectromagnetic InductionActual
A conducting rod P Q of length 1 ~m is moving with a uniform speed 2 ~ms ⁻¹ in a uniform magnetic field of 4 ~T which is directed into the paper. A capacitor of capacity 10 F is connected as shown in the figure. Then, the charge on the plates of the capacitor are
Options
- Aq_A=+80 C , q_B=-80 C
- Bq_A=-80 C , q_B=+80 C
- Cq_A=+1.25 C , q_B=1.25 C
- Dq_A=-1.25 C , q_B=+1.25 C
Correct answer
A. q_A=+80 C , q_B=-80 C
Step-by-step solution
Charge on each plate should be aligned & q=C V & V=v B l & q=C(v B l) & =10 10⁻⁶ 2 4 1 & q=80 C & aligned where, So, charges on plates are 80 C .