A coil of wire of radius r has 600 turns and a self inductance of 108 mH . The self inductance of a coil with same radius and 500 turns is

Step-by-step solution

The given, L₁=108 mH , N₁=600 turns, N₂=500 turns and L₂= ? By self-inductance of a plane coil aligned & L₁= ₀ N₁^2 a₁ 2 & L₂= ₀ N₂^2 a₂ 2 aligned From the Eqs. (i) and (ii), we get aligned L₁ L₂ & = ( N₁ N₂ )^2 ( a₁=a₂ ) 108 L₂ & = ( 600 500 )^2 L₂ & = 108 25 36 L₂ & =3 25=75 mH aligned