AP EAMCET20226 Jul 2022Morning ShiftPhysicsElectrostaticsActual
A wire of length L has a charge Q distributed uniformly along its length. The wire is bent in the shape of a semicircle. The magnitude of the electric field at the centre of curvature of the semicircle is
Options
- A1 4 ₀ Q L^2
- B1 4 ₀ Q^2 L
- CQ 2 _ o 1 ~L ^2
- D1 2 ₀ Q L ^2
Correct answer
C. Q 2 _ o 1 ~L ^2
Step-by-step solution
We have aligned & dQ = dl & = Rd & So, dE = 1 4 ₀ Rd R ^2 & = 1 4 ₀ d R aligned So, E = dE = 1 4 ₀ R _ - / 2 ^ + / 2 d = 2 4 ₀ R = 2 4 ₀ Q / L L / = Q 2 ₀ 1 ~L ₂ [ L = R and = Q L ]