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AP EAMCET20226 Jul 2022Morning ShiftPhysicsElectrostaticsActual

An infinite non-conducting sheet has a surface charge density of 7 10⁻⁷ C m ⁻² on one side. The distance between equipotential surfaces whose potentials differ by 19.8 ~V , will be (Take 1 4 _ o =9 10^9 SI units)

Options

  1. A2.0 ~mm
  2. B0.25 ~mm
  3. C1.0 ~mm
  4. D0.5 ~mm

Correct answer

D. 0.5 ~mm

Step-by-step solution

We have aligned & | E |= V r = 19.8 r & 2 ₀ = 19.8 r & r = 19.8 2 ₀ = 19.8 2 8.85 10⁻¹² 7 10⁻⁷ & =5 10⁻⁴ ~m & =0.5 ~mm aligned

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