An electric charge 10⁻³ C is placed at the origin (0,0) of (x-y) co-ordinate system. Two points A and B are situated at ( 2 , 2 ) and (2,0) respectively. The potential difference between the points A and B will be

Step-by-step solution

aligned & r₁ = 2 i + 2 j & | r ₁ |=r₁= ( 2 )^2+( 2 )^2 =2 aligned aligned & r ₂=2 i +0 j & or | r ₂ |=r₂=2 aligned Potential at point A is aligned & V_A= 1 q 4 ₀ r₁ & = 1 4 ₀ 10⁻³ 10⁻⁶ 2 aligned Potential at point B is aligned & V_B= 1 4 ₀ q r₂ = 1 4 ₀ 10⁻³ 10⁻⁶ 2 & V_A-V_B=0 . aligned