An imaginary equilateral triangle A B C of side length 2 m is placed in a uniform electric field E → = 10 N C - 1 as shown. Then. V A - V B =

Step-by-step solution

Here angle ϕ = 60 ° Potential difference in uniform electric field is given by ∆ v = - E r cos ϕ ⇒ ∆ v = - 10 × 2 cos 60 = - 10   v