AP EAMCET202022 Sep 2020Morning ShiftPhysicsElectrostaticsActual
When a 5 C charge is kept in a uniform electric field, a force of 5000 ~N acts on it. Find the potential difference between two points in that field, separated by a distance of 1 ~cm .
Options
- A10 ~V
- B250 ~V
- C) 1000 ~V
- D2500 ~V
Correct answer
A. 10 ~V
Step-by-step solution
Charge, q=5 C Force, aligned & F=5000 ~N & d=1 ~cm =10⁻² ~m aligned Potential difference between the given points, aligned V & =B d= F q d & [ B= F q ] & = 5000 5 10⁻²=10 ~V & aligned