AP EAMCET201921 Apr 2019Morning ShiftPhysicsElectrostaticsActual
The potential difference (V_A-V_B ) in the arrangement shown in the figure is (q=1 C , x=2 ~cm , y=3 ~cm )
Options
- A5.4 10^5 ~V
- B2.7 10^5 ~V
- C5.4 10^2 ~V
- D2.7 10^2 ~V
Correct answer
A. 5.4 10^5 ~V
Step-by-step solution
An arrangement is shown in the figure below, Here, potential at a point A , gathered V_A=V_ A^ +q +V_ A^ -q = 9 10^9 10⁻⁶ 2 10⁻² - 9 10^9 10⁻⁶ 5 10⁻² =9 10^5 [ 1 2 - 1 5 ] gathered Similarly, potential at a point B , V_B=V_ B^ +q +V_ B^ -q =9 10^5 [ 1 5 - 1 2 ] Hence, V_A-V_B=9 10^5 [ 1 2 - 1 5 - 1 5 + 1 2 ] V_A-V_B=5.4 10^5 ~V Hence, the correct option is (a).