Three charges of each magnitude (100 C ) are placed at the corners (A, B ) and (C ) of an equilateral triangle of side (4 ~m ). If the charges at points (A ) and (C ) are positive and the charge at point (B ) is negative, then the magnitude of total force acting on the charge at (C ) and angle made by it with (A C ) are

Step-by-step solution

According to the question, we can draw the following diagram, From the question, it clear that the charge on the each corner is (100 C ). So, ( aligned F_ net & =F & = k Q₁ Q₂ r^2 aligned ) Given, (Q₁=Q₂=100 C =100 10⁻⁶ C , [1 C =10⁻⁶ C ] ) and (r=4 ~m ) Putting the given values in Eq. (i), we get ( aligned & = 9 10^9 (100 10⁻⁶ )^2 (4)^2 F_ net & =5.625 ~N , 60^ aligned )