AP EAMCET201823 Apr 2018Evening ShiftPhysicsElectrostaticsActual
Electric field vector in a region is given by E =(3 i +4 y j ) V - m ⁻¹ . The potential at the origin is zero. Then, the potential at a point (2,1) m is
Options
- A7 V
- B8 V
- C-8 V
- D-7 V
Correct answer
C. -8 V
Step-by-step solution
gathered As, E= - V_x x i + - V_y y j - V_x x =3 and - V_y y =4 y V_x=-3 x and V_y=-2 y^2 gathered So, V= potential function =- (3 x+2 y^2 ) Potential at point (2,1) is V=- (3 2+2 1^2 )=-8 ~V