Two infinitely long parallel conducting plates having surface charge densities +σ and -σ respectively, are separated by a small distance. The medium between the plates is vacuum. If _0 is the dielectric permittivity of

Correct answer: C. σ / _0 volt / metre Electric field between the plates is aligned & =(σ)/(2 _0)-((-σ))/(2 _0) & =(σ)/( _0) volt / meter aligned

AIIMS 2005

Exam: AIIMS
Year: 2005
Subject: Physics
Chapter: Electrostatics

AIIMS 2005 · Physics · Electrostatics

Two infinitely long parallel conducting plates having surface...

Two infinitely long parallel conducting plates having surface charge densities

+\sigma

and

-\sigma

respectively, are separated by a small distance. The medium between the plates is vacuum. If

\varepsilon_0

is the dielectric permittivity of vacuum, then the electric field in the region between the plates is Two infinitely long parallel conducting plates having surface charge densities +σ and -σ respectively, are separated by

Two infinitely long parallel conducting plates having surface charge densities +σ and -σ respectively, are separated by

Options

A0 volt/metre
B $\sigma / 2 \varepsilon_0$ volt $/$ metre
C $\sigma / \varepsilon_0$ volt $/$ metre
D $2 \sigma / \varepsilon_0$ volt/metre.

Correct answer

C. $\sigma / \varepsilon_0$ volt $/$ metre

Step-by-step solution

Electric field between the plates is

\begin{aligned}& =\frac{\sigma}{2 \varepsilon_0}-\frac{(-\sigma)}{2 \varepsilon_0}\\ & =\frac{\sigma}{\varepsilon_0} \text{ volt }/ \text{ meter } \end{aligned}

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