AP EAMCET2014PhysicsElectrostatics
Two concentric hollow spherical shells have radii r and R(R r) . A charge Q is distributed on them such that the surface charge densities are equal. The electric potential at the centre is
Options
- AQ(R+r) 4 ₀ (R^2+r^2 )
- BQ (R^2+r^2 ) 4 ₀(R+r)
- CQ (R+r)
- Dzero
Correct answer
A. Q(R+r) 4 ₀ (R^2+r^2 )
Step-by-step solution
We know that, the surface charge densities is = Q 4 (r^2+R^2 ) The electric potential at the centre aligned V & = 1 4 ₀ [ 4 r^2 r + 4 R^2 R ] & = 1 4 ₀ 4 [ r^2 r + R^2 R ] & = ₀ (r+R) aligned and V= Q ₀ 4 (r^2+R^2 ) (r+R) V= Q 4 ₀ (r+R) (r^2+R^2 )