AP EAMCET2008PhysicsElectrostatics
A charge of 1 C is divided into two parts such that their charges are in the ratio of 2: 3 . These two charges are kept at a distance 1 ~m apart in vacuum. Then, the electric force between them ( in N) is
Options
- A0.216
- B0.00216
- C0.0216
- D2.16
Correct answer
B. 0.00216
Step-by-step solution
Ratio of charges =2: 3 q₁= 2 5 1 C and q₂= 3 5 1 C Electrostatic force between the two charges aligned F & = 1 4 ₀ q₁ q₂ r^2 & = 9 10^9 2 10⁻⁶ 3 10⁻⁶ 5 5 (1)^2 & =2.16 10⁻³ ~N aligned