Two electric charges of 9 C and -3 C are placed 0.16 ~m apart in air. There will be a point ' P ', at which electric potential is zero on the line joining two charges and in between them. The distance of P from 9 C is

Step-by-step solution

q₁=9 C , q_x=-3 C , r=0.16 ~m Potential at point ' P ', V₁+V₃=0 or V₁=-V₂ aligned 1 4 x₁ q₁ r₁ & = -1 4 x₀ q₃ r₂ 9 x & = -(-3) (0.16-x) aligned aligned 3(0.16-x) & =x 0.48-3 x & =x 4 x=0.48 x & =0.12 ~m aligned