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AIIMS 2003
Exam
AIIMS
Year
2003
Subject
Physics
Chapter
Electrostatics

AIIMS 2003 · Physics · Electrostatics

Figure shown is a distribution of charges. The flux of electric...

Figure shown is a distribution of charges. The flux of electric field due to these charges through the surface SS is Figure shown is a distribution of charges. The flux of electric field due to these charges through the surface S is

Options

  1. A3q/ε03 q / \varepsilon_0
  2. B2q/ε02 q / \varepsilon_0
  3. Cq/ε0q / \varepsilon_0
  4. Dzero.

Correct answer

D. zero.

Step-by-step solution

According to Gauss's law, the total electric flux through a closed surface is given by ϕ=∮sE⃗⋅ds⃗=Qε0\phi=\oint_s \vec{E} \cdot d \vec{s}=\frac{Q}{\varepsilon_0} where QQ is the total charge enclosed by the surface. The total charge enclosed by the given surface is Q=+q−q=0.∴Q=+q-q=0 . \quad \therefore The total flux ϕ=0\phi=0.
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