Height of geostationary satellite is

The principle of the geostationary satellite is its period of rotation is the same as that of the earth. ($\frac{-G M m}{r^2}+$m \omega^2 r=0) i.e. (\frac{G M}{(R+h)^2}=\left(\frac{2 \pi}{T}\right)^2(R+h)) $h$ works out to (36000 $\mathrm{~km}$).