BITSAT2017ChemistryAminesActual
In the reaction, CH 3 · CH 2 · Cl ⟶ KCN A ⟶ LiAlH 4 P end product P is
Options
- ACH 3 CH 2 · NO 2
- BCH 3 CH 2 CH 2 NO 2
- CCH 3 CH 2 NH 2
- DCH 3 · CH 2 · CH 2 NH 2
Correct answer
D. CH 3 · CH 2 · CH 2 NH 2
Step-by-step solution
When the reducing agent is lithium aluminium hydride, the aldehyde group is reduced to primary alcohol but the carbon-carbon double bond is unaffected. In the given reaction the end product is (d). It is obtained as follows. CH 3 CH 2 · Cl ⟶ KCN CH 3 CH 2 CN ( A ) → ( Reduction ) LiAlH 4 CH 3 CH 2 CH 2 · NH 2