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BITSAT 2017

Exam: BITSAT
Year: 2017
Subject: Chemistry
Chapter: Amines

BITSAT 2017 · Chemistry · Amines

Maximum pK _ b & value is of&

Maximum

{pK}_{b}

& value is of& Maximum pK _ b & value is of&

Maximum pK _ b & value is of&

Maximum pK _ b & value is of&

Maximum pK _ b & value is of&

Options

A
B $\left({CH}_{3}{CH}_{2}\right)2NH$
C $\left({CH}_{3}\right)2NH$
D

Correct answer

D. Azimuthal quantum number ( ) defined

Step-by-step solution

Maximum ${pK}_{b}$ (least basic) is (d) since, lone pair on
N-atom is used to delocalise $\pi$ -electrons on two benzene
rings.

Maximum pK _ b & value is of&

Least basic has maximum value of ${pK}_{b}$ .

Since, in (d), lone pair of electrons over $N$ -atom are delocalised to two benzene rings, thus is least basic.

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