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BITSAT 2020
Exam
BITSAT
Year
2020
Subject
Chemistry
Chapter
Chemical Equilibrium

BITSAT 2020 · Chemistry · Chemical Equilibrium

The ratio K_ p K_ c for the reaction CO(g)+(1)/(2) O_ 2 (g)...

The ratio KpKc\frac{K_{p}}{K_{c}} for the reaction CO(g)+12O2(g)⇌CO2(g)\mathrm{CO}(g)+\frac{1}{2} \mathrm{O}_{2}(g) \rightleftharpoons \mathrm{CO}_{2}(g) is:

Options

  1. A1RT\frac{1}{\sqrt{R T}}
  2. B(RT)1/2(R T)^{1 / 2}
  3. CRT\mathrm{RT}
  4. D1

Correct answer

A. 1RT\frac{1}{\sqrt{R T}}

Step-by-step solution

KP=KC(RT)Δng K_{P}=K_{C}(R T)^{\Delta n_{\text{g }}} For the reaction CO(g)+12O2(g)⇋CO2(g)Δng=1−(1+12)=−12∴KP=KCRT;KPKC=1RT\mathrm{CO}(\mathrm{g})+\frac{1}{2} \mathrm{O}_{2}(g) \leftrightharpoons \mathrm{CO}_{2}(\mathrm{ g})\Delta n_{g}=1-\left(1+\frac{1}{2}\right)=-\frac{1}{2}\therefore \quad \mathrm{K}_{\mathrm{P}}=\frac{\mathrm{K}_{\mathrm{C}}}{\sqrt{\mathrm{RT}}} ; \quad \frac{\mathrm{K}_{\mathrm{P}}}{\mathrm{K}_{\mathrm{C}}}=\frac{1}{\sqrt{\mathrm{RT}}}
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