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BITSAT 2016
Exam
BITSAT
Year
2016
Subject
Chemistry
Chapter
Chemical Equilibrium

BITSAT 2016 · Chemistry · Chemical Equilibrium

In a closed system, A(s) leftharpoons 2 B( g)+3 C(g) , if partial...

In a closed system, A(s)⇌2B(g)+3C(g)\mathrm{A}(\mathrm{s}) \rightleftharpoons 2 \mathrm{ B}(\mathrm{ g})+3 \mathrm{C}(\mathrm{g}), if partial pressure of C\mathrm{C} is doubled, then partial pressure of B\mathrm{B} will be

Options

  1. A222 \sqrt{2} times the original value
  2. B12\frac{1}{2} times the original value
  3. C2 times the original value
  4. D122\frac{1}{2 \sqrt{2}} times the original value

Correct answer

D. 122\frac{1}{2 \sqrt{2}} times the original value

Step-by-step solution

Kp=pB12×pC13\quad K_{p}=p_{B_{1}}^{2} \times p_{C_{1}}^{3} Again, Kp=pB22×(2pC1)3∴pB12×pC13=PB22×8pC13∴pB128=pB22 or, pB122=pB2K_{p}=p_{B_{2}}^{2} \times\left(2 p_{C_{1}}\right)^{3}\therefore \mathrm{p}_{\mathrm{B}_{1}}^{2} \times \mathrm{p}_{\mathrm{C}_{1}}^{3}=\mathrm{P}_{\mathrm{B}_{2}}^{2} \times 8 \mathrm{p}_{\mathrm{C}_{1}}^{3} \therefore \frac{\mathrm{p}_{\mathrm{B}_{1}}^{2}}{8}=\mathrm{p}_{\mathrm{B}_{2}}^{2} \text{ or, } \frac{\mathrm{p}_{\mathrm{B}_{1}}}{2 \sqrt{2}}=\mathrm{p}_{\mathrm{B}_{2}}
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