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BITSAT 2019
Exam
BITSAT
Year
2019
Subject
Chemistry
Chapter
Chemical Equilibrium

BITSAT 2019 · Chemistry · Chemical Equilibrium

4 moles of A are mixed with 4 moles of B . At equilibrium for the...

44 moles of AA are mixed with 44 moles of BB. At equilibrium for the reaction A+B⇌C+D,2A + B ⇌ C + D, 2 moles of CC and DD are formed, the equilibrium constant for the reaction will be,

Options

  1. A11
  2. B1/21 / 2
  3. C44
  4. D1/41 / 4

Correct answer

A. 11

Step-by-step solution

The initial concentrations of A, B, C, and D are 4M, 4M, 0M, and 0M respectively.

The equilibrium concentrations of A,B,C and D are& 4−2=2M,& 4−2=2M, 2M and 2M respectively.

A+B⇌C+Dinitialconc4400atequilibrium(4−2)(4−2)22A + B ⇌ C + Dinitialconc4400atequilibrium\left(4 - 2\right)\left(4 - 2\right)22

The expression for the equilibrium constant is =[C][D][A][B]= \dfrac{[ C ] [ D ] }{[ A ] [ B ]}

∴K(eq)=2×22×2=1∴ K\left(eq\right) = \dfrac{2 \times 2}{2 \times 2} = 1

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