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BITSAT2024ChemistryChemical KineticsActual

Calculate the activation energy of a reaction, whose rate constant doubles on raising the temperature from 300 K to 600 K .

Options

  1. A3.45 ~kJ / mol
  2. B6.90 ~kJ / mol
  3. C9.68 ~kJ / mol
  4. D19.6 ~kJ / mol

Correct answer

A. 3.45 ~kJ / mol

Step-by-step solution

( k₂ k₁ )= E_a 2.303 R [ 1 T₁ - 1 T₂ ] or, ( 2 k k )= E_a 2.303 8.3 [600-300] 300 600 E_a 3.45 ~kJ / mol

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