Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
BITSAT2024ChemistryChemical KineticsActual

In a first order reaction, the concentration of the reactant, decreases from 0.8 M to 0.4 M in 15 minutes. The time taken for the concentration to change from 0.1 M to 0.025 M is

Options

  1. A7.5 minutes
  2. B15 minutes
  3. C30 minutes
  4. D60 minutes

Correct answer

C. 30 minutes

Step-by-step solution

As the concentration of reactant decreases from 0.8 to 0.4 in 15 minutes, hence the t_ 1 / 2 is 15 minutes. To fall the concentration from 0.1 to 0.025 , we need two half lives, i.e., 30 minutes.

Practice Chemical Kinetics on Quantrex Academy →

More from Chemical Kinetics

For the reaction 2 SO ₂+ O ₂ 2 SO ₃ , the rate of disappearance of O ₂ is 2 10⁻⁴ ~mol ~L ⁻¹ s ⁻¹ . The rate appearance of SO ₃ is 2024If for a first order reaction, the value of A and E_a are 4 10¹³ ~s ⁻¹ and 98.6 ~kJ ~mol ⁻¹ respectively, then at what temperature will its half life period be 10 minutes? 2024In the chemical reaction A B , what is the order of the reaction? Given that, the rate of reaction doubles if the concentration of A is increased four times. 2024Calculate the activation energy of a reaction, whose rate constant doubles on raising the temperature from 300 K to 600 K . 2024In the reaction, A products, If the concentration of the reactant is doubled rate of the reaction remains unchanged. The order of the reaction with respect to A is 2024For the decomposition of azomethane, CH ₃ ~N ₂ CH ₃( ~g ) CH ₃ CH ₃( ~g )+ N ₂( ~g ) a first order reaction, the variation in partial pressure with time at 600 ~K is given as The h 2023Plots showing the variation of the rate constant (k) with temperature (T) are given below. The plot that follows Arrhenius equation is 2023In a 1 st order reaction, reactant concentration C varies with time t as : 2021 Full Chemical Kinetics list All BITSAT PYQs