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BITSAT 2016
Exam
BITSAT
Year
2016
Subject
Chemistry
Chapter
Coordination Compounds

BITSAT 2016 · Chemistry · Coordination Compounds

Which of the following is paramagnetic?

Which of the following is paramagnetic?

Options

  1. A[Fe(CN)6]4−\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{4-}
  2. B[Ni(CO)4]\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]
  3. C[Ni(CN)4]2−\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}
  4. D[CoF6]3−\left[\mathrm{CoF}_{6}\right]^{3-}

Correct answer

D. [CoF6]3−\left[\mathrm{CoF}_{6}\right]^{3-}

Step-by-step solution

Fe2+\mathrm{Fe}^{2+} electronic configuration is [Ar]3d6[\mathrm{Ar}] 3 \mathrm{ d}^{6}. Since CN is strong field ligand d electrons are paired. In Ni(CO)4O.S\mathrm{Ni}(\mathrm{CO})_{4} \mathrm{O}. \mathrm{S}. of Ni\mathrm{Ni} is zero electronic configuration is [Ar}3d84s2.In[\mathrm{Ar}\} 3 \mathrm{ d}^{8} 4 \mathrm{ s}^{2}. \mathrm{In} presence of CO\mathrm{CO} it is [Ar]3d104s0,[\mathrm{Ar}] 3 \mathrm{ d}^{10} 4 \mathrm{ s}^{0}, electrons are paired. Electronic configuration of Ni2+[Ar]3d84s0,\mathrm{Ni}^{2+}[\mathrm{Ar}] 3 \mathrm{ d}^{8} 4 \mathrm{ s}^{0}, due to CN−\mathrm{CN}^{-} ligand all electrons are paired. Co3+\mathrm{Co}^{3+} is [Ar]3d6[\mathrm{Ar}] 3 \mathrm{ d}^{6} since F\mathrm{F} is weak ligand hence paramagnetic.
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