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BITSAT 2019
Exam
BITSAT
Year
2019
Subject
Chemistry
Chapter
d and f Block Elements

BITSAT 2019 · Chemistry · d and f Block Elements

Which of the following lanthanoid is diamagnetic? Atomic no's Sm =...

Which of the following lanthanoid is diamagnetic?

Atomic no's Sm=62,Ce=58,Eu=63,Yb=70Sm = 62, Ce = 58, Eu = 63, Yb = 70

Options

  1. ASm2+{Sm}^{2 +}
  2. BEu2+{Eu}^{2 +}
  3. CYb2+{Yb}^{2 +}
  4. DCe2+{Ce}^{2 +}

Correct answer

C. Yb2+{Yb}^{2 +}

Step-by-step solution

Electronic configuration of the given species are

a. Sm2+(Z=62)=[Xe]4f6{Sm}^{2 +}\left(Z = 62\right) = \left[Xe\right]4f^{6} b. Eu2+(Z=63)=[Xe]4f7{Eu}^{2 +}\left(Z = 63\right) = \left[Xe\right]4f^{7}

c. Yb2+(Z=70)=[Xe]4f14{Yb}^{2 +}\left(Z = 70\right) = \left[Xe\right]4f^{14} d. Ce2+(Z=58)=[Xe]4f15d1{Ce}^{2 +}\left(Z = 58\right) = \left[Xe\right]4f^{1}5d^{1}

On the basis of above electronic configuration, only Yb2+(Z=70)hasnounpairedelectronsi.e.hasfully−filledorbitals.Thus,itisdiamagneticinnature.</p>{Yb}^{2 +} \left(Z = 70\right) has no unpaired electrons i.e. has fully-filled orbitals. Thus, it is diamagnetic in nature.</p>

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