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BITSAT 2018
Exam
BITSAT
Year
2018
Subject
Chemistry
Chapter
d and f Block Elements

BITSAT 2018 · Chemistry · d and f Block Elements

Which among the following actinoids does not have stable electronic...

Which among the following actinoids does not have stable electronic configuration

Options

  1. AProtactinium
  2. BNobelium
  3. CAmericium
  4. DLawrencium

Correct answer

A. Protactinium

Step-by-step solution

Protactinium (Pa)\left(Pa\right) is the element that does not have stable electronic configuration.

Protactinium (Pa)=[Rn]5f26d17s2\left(Pa\right) = \left[Rn\right]5f^{2}6d^{1}7s^{2} (Atomic number =91= 91)

Nobelium \left(No\right) = \left(Rn\right)5f^{14}6d^{0}7s^{2} (Atomicnumber~(Atomic number= 102)</p><p>Lawrencium(Lr)=[Rn]5f146d17s2)</p><p>Lawrencium \left(Lr\right) = \left[Rn\right]5f^{14}6d^{1}7s^{2} (Atomic number =103= 103)

Americium \left(Am\right) = \left[Rn\right]5f^{7}6d^{0}7s^{2}(Atomicnumber(Atomic number= 95)

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