The pH of 0.5 L of 1.0 M NaCl solution after electrolysis for 965 s using 5.0 A current is,

Step-by-step solution

The reaction involved is, NaCl + H ₂ O Electrolysis 1 2 H ₂+ Cl ₂+ NaOH Amount of NaCl present in 0.5 L of 1.0 M , NaCl =0.5 mol Quantity of electricity passed =965 5 coulombs. 4825 coulombs will decompose NaCl . aligned & = 4825 96500 ~mol & =0.05 ~mol aligned NaOH formed in the solution will also be 0.05 mol . Volume of solution =0.5 ~L Molarity of NaOH in the solution aligned & = 0.05 moles 0.5 ~L =0.1 M & =10⁻¹ M aligned array rlrl & & pOH & =1 or & pH & =14-1=13 array