BITSAT 2023Paper 2
- Exam
- BITSAT
- Year
- 2023
- Paper
- Paper 2
- Subject
- Chemistry
- Chapter
- Electrochemistry
BITSAT 2023 · Paper 2 · Chemistry · Electrochemistry
Given that E_ O_2 / H_2 O^ ^ =+1.23 V ; aligned & E_ S_2 O_8^ 2- /...
Given that E_{\mathrm{O}_2 / \mathrm{H}_2 \mathrm{O}^{{}^{\circ}}=+1.23 \mathrm{ V};
\begin{aligned} \\ & E_{\mathrm{S}_2 \mathrm{O}_8^{2-} / \mathrm{SO}_4^{2-}}^{{}^{\circ}}=2.05 \mathrm{ V} ; E_{\mathrm{Br}_2 / \mathrm{Br}^{-}}^{{}^{\circ}}=+1.09 \mathrm{ V} \\ \\ & E_{\mathrm{Au}^{3+} / \mathrm{Au}^{{}^{\circ}}=+1.4 \mathrm{ V} \\ \end{aligned}
The strongest oxidising agent is :
\begin{aligned} \\ & E_{\mathrm{S}_2 \mathrm{O}_8^{2-} / \mathrm{SO}_4^{2-}}^{{}^{\circ}}=2.05 \mathrm{ V} ; E_{\mathrm{Br}_2 / \mathrm{Br}^{-}}^{{}^{\circ}}=+1.09 \mathrm{ V} \\ \\ & E_{\mathrm{Au}^{3+} / \mathrm{Au}^{{}^{\circ}}=+1.4 \mathrm{ V} \\ \end{aligned}
The strongest oxidising agent is :
Options
- A
- B
- C
- D
Correct answer
C.
Step-by-step solution
Reduction potential is maximum for therefore, it is the strongest oxidising agent amongst the given species.