Electrode potential data are given below: Fe^ +3 (aq)+ ^ - Fe^ +2 (aq) ; E^ ^ =+0.77 V Al^ 3+ (aq)+3 ^ - Al_ (s) ; E^ ^ =-1.66 V Br_2(aq)+2 ^ - 2 Br^ - (aq) ; E^ ^ =+1.08 V Based on the data, the reducing power of Fe^

Correct answer: A. Br^ - Fe^ 2+ > Br

BITSAT 2023Paper 1

BITSAT 2023 · Paper 1 · Chemistry · Electrochemistry

Electrode potential data are given below: Fe^ +3 (aq)+ ^ - Fe^ +2...

Electrode potential data are given below:

\mathrm{Fe}^{+3}(\mathrm{aq})+\mathrme^{-} \longrightarrow \mathrm{Fe}^{+2}(\mathrm{aq}) ; \mathrm{E}^{{}^{\circ}}=+0.77 \mathrm{ V}

\mathrm{Al}^{3+}(\mathrm{aq})+3 \mathrme^{-} \longrightarrow \mathrm{Al}_{(\mathrm{s})} ; \mathrm{E}^{{}^{\circ}}=-1.66 \mathrm{ V}

\mathrm{Br}_2(\mathrm{aq})+2 \mathrme^{-} \longrightarrow 2 \mathrm{Br}^{-}(\mathrm{aq}) ; \mathrm{E}^{{}^{\circ}}=+1.08 \mathrm{ V}

Based on the data, the reducing power of

\mathrm{Fe}^{2+}

\mathrm{Al}

and

\mathrm{Br}^{-}

will increase in the order

A. $\mathrm{Br}^{-} < \mathrm{Fe}^{2+} < \mathrm{Al}$

$\begin{array}{rrrr} & \text{ Fe } & \text{ A1 } & \text{ B } \\ E_{\text{Red }}^{{}^{\circ}} & 0.77 & -1.66 & 1.08 \\ E_{\text{Oxi }}^{{}^{\circ}} & -0.77 & 1.66 & -1.08\end{array}

\\ Hence, reducing power

\mathrm{Al}

\mathrm{Fe}^{2+}

\mathrm{Br}