pH of a saturated solution of Ba OH 2 is 12 . The value of its K sp is

Step-by-step solution

Given that, pH of Ba OH 2 = 12 ∵   pH + pOH = 14 ∴   pOH = 14 - pH = 14 - 12 = 2 Now, pOH = - log OH - ⇒   2 = - log OH OH - = 10 - 2   M Ba OH 2 s S   mol   L - 1 ⇌ Ba 2 + S + 2 OH - 2 S OH - = 2 S = 10 - 2   M ∴   S = 0 . 5 × 10 - 2 = 5 × 10 - 3   M K sp = Ba 2 + OH - 2 ⇒ ( 5 × 10 - 3 ) ( 10 - 2 ) 2 = 5 × 10 - 7 M 3 Therefore, the value of   K sp is 5 . 0 × 10 - 7   M 3 .