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BITSAT 2021
Exam
BITSAT
Year
2021
Subject
Chemistry
Chapter
p Block Elements (Group 13 & 14)

BITSAT 2021 · Chemistry · p Block Elements (Group 13 & 14)

Diborane (B_ 2 H_ 6 ) reacts independently with O_ 2 and H_ 2 O to...

Diborane (B2H6)\left(\mathrm{B}_{2} \mathrm{H}_{6}\right) reacts independently with O2andH2O\mathrm{O}_{2} and \mathrm{H}_{2} \mathrm{O} to produce, respectively:

Options

  1. AB2O3\mathrm{B}_{2} \mathrm{O}_{3} and H3BO3\mathrm{H}_{3} \mathrm{BO}_{3}
  2. BB2O3\mathrm{B}_{2} \mathrm{O}_{3} and [BH4]−\left[\mathrm{BH}_{4}\right]^{-}
  3. CH3BO3\mathrm{H}_{3} \mathrm{BO}_{3} and B2O3\mathrm{B}_{2} \mathrm{O}_{3}
  4. DHBO2\mathrm{HBO}_{2} and H3BO3\mathrm{H}_{3} \mathrm{BO}_{3}

Correct answer

A. B2O3\mathrm{B}_{2} \mathrm{O}_{3} and H3BO3\mathrm{H}_{3} \mathrm{BO}_{3}

Step-by-step solution

B2H6+3O2→B2O3+3H2OB2H6+6H2O→2H3BO3+6H2\mathrm{B}_{2} \mathrm{H}_{6}+3 \mathrm{O}_{2} \rightarrow \mathrm{B}_{2} \mathrm{O}_{3}+3 \mathrm{H}_{2} \mathrm{O}\mathrm{B}_{2} \mathrm{H}_{6}+6 \mathrm{H}_{2} \mathrm{O} \rightarrow 2 \mathrm{H}_{3} \mathrm{BO}_{3}+6 \mathrm{H}_{2}
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