0 . 45 g acid of molecular mass 90 was neutralise by 20 ml of 0 . 5 N KOH . The basicity of the acid is

Step-by-step solution

Given that 0 . 45   g of the acid of molecular mass 90 was neutralized by 20   ml of 0 . 5   N caustic potash. We know that, Normality   N   =   Weight   of   the   base   × 1000 Eq .   weight × volume ∵ Gram equivalents of an acid Gram equivalents of KOH i.e. 0 . 45 E = 20 × 0 . 5 1000 where, E = Equivalent mass E = 0 . 45 × 1000 20 × 0 . 5 = 45 Thus, basicity = 90 45 = 2 ∵ Basicity = Molecular mass Equivalent mass