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BITSAT 2018
Exam
BITSAT
Year
2018
Subject
Chemistry
Chapter
Redox Reactions

BITSAT 2018 · Chemistry · Redox Reactions

Which of the following statements is incorrect regarding the...

Which of the following statements is incorrect regarding the equation
MeCHO+[Ag(NH3)2]++O¯H⟶MeCOO−+AgMeCHO + \left[Ag\left({NH}_{3}\right)^{2}\right] + + \overset{¯}{O}H ⟶ {MeCOO}^{-} + Ag

Options

  1. AThe equivalent weight of MeCHOMeCHO is 2222.
  2. BThree moles of O¯H\overset{¯}{O}H are required in the reaction.
  3. CMeCHOMeCHO acts as an oxidising agent.
  4. D[Ag(NH3)2]+\left[Ag\left({NH}_{3}\right)2\right] + gets reduced.

Correct answer

C. MeCHOMeCHO acts as an oxidising agent.

Step-by-step solution

Oxidation :&
CH3COO−+3O¯H→CH3COO−+2e−+2H2O{CH}_{3}{COO}^{-} + 3\overset{¯}{O}H \to {CH}_{3}{COO}^{-} + 2e^{-} + 2{H}_{2}O

Reduction :~\left\left[Ag\left({NH}_{3}\right)2\right] + + e^{-} ⟶ Ag + {NH}_{3}\right] \times 2</p><p></p><p>{CH}_{3}CHO + 2\left[Ag\left({NH}_{3}\right)2\right] + + 3\overset{¯}{O}H ⟶ {CH}_{3}O\overset{¯}{O} + 2{H}_{2}O

Molecular mass \left(M\right)ofCH3CHO=44gmol−1</p><p>Equivalentweight(Eω)=Mn−factor=442=22gmol−1of {CH}_{3}CHO = 44g{mol}^{- 1}</p><p>Equivalent weight \left(E \omega\right) = \dfrac{M}{n - factor} = \dfrac{44}{2} = 22g{mol}^{- 1}

Since aldehyde is getting oxidised therefore, it is acting as reducing agent and not oxidising agent.

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