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BITSAT 2024
Exam
BITSAT
Year
2024
Subject
Chemistry
Chapter
Solutions

BITSAT 2024 · Chemistry · Solutions

A decimolar solution potassium ferrocyanide is 50 \% dissociated at...

A decimolar solution potassium ferrocyanide is 50%50 \% dissociated at 300 K . The osmotic pressure of solution is (R=8.314JK−1 mol−1)\left(R=8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\right)

Options

  1. A7.48 atm
  2. B4.99 atm
  3. C3.74 atm
  4. D6.23 atm

Correct answer

A. 7.48 atm

Step-by-step solution

α=0.5\alpha=0.5 (50\% dissociated) The reaction involves is Total moles at equilibrium =1−α+4α+α Total =1+4α∴=1-\alpha+4 \alpha+\alpha\text{ Total }=1+4 \alpha\therefore van't Hoff factor (i)=1+4α1=1+4×0.5=3(i)=\frac{1+4 \alpha}{1}=1+4 \times 0.5=3 Osmotic pressure, π=iCRT\pi=i C R TC=0.1M=102molm−3π=3×102×8.314×300=7.483×105Nm−2\begin{aligned} C & =0.1 \mathrm{M}=10^2 \mathrm{ mol} \mathrm{ m}^{-3} \\ \pi & =3 \times 10^2 \times 8.314 \times 300 \\ & =7.483 \times 10^5 \mathrm{Nm}^{-2} \end{aligned}$oror\pi=7.48 \mathrm{ atm}$
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