58.5 g of NaCl and 180 g of glucose were separately dissolved in...

$$\begin{aligned} 58.5 \mathrm{ g} \mathrm{NaCl} & =\frac{58.5}{58.5} \mathrm{ mol} \\ & =1 \mathrm{ mol} \\ 180 \mathrm{ g} \text{ of glucose } & =\frac{180}{180}=1 \mathrm{ mol} \end{aligned}$$ Thus, we have 1 M NaCl and 1 M glucose solution. But NaCl dissociates in the solution and glucose does not dissociates. Thus particle concentration is more in NaCl . Hence, NaCl solution will have higher elevation in boiling point.