BITSAT 2019
- Exam
- BITSAT
- Year
- 2019
- Subject
- Chemistry
- Chapter
- Solutions
BITSAT 2019 · Chemistry · Solutions
An aqueous solution freezes at 272. 4K , while pure water freezes...
An aqueous solution freezes at , while pure water freezes at , given , and the molality of solution and boiling point of solution respectively will be -
Options
- A and
- B and
- C and
- D and
Correct answer
A. and
Step-by-step solution
Depression in freezing point is given as
Molality of solution \left(m\right) = \dfrac{\Delta Tf}{Kf}m = \dfrac{0 . 6}{1 . 86} = 0 . 322m{ΔT}_{b} = {k}_{b} \times m{ΔT}_{b} = 0 . 512 \times 0 . 322{ΔT}_{b} = 0 . 165∴= 373 + 0 . 16= 373 . 16K