An aqueous solution freezes at 272 . 4 K , while pure water freezes at 273 K , given K f = 1 . 86 K kg mol - 1 , and K b = 0 . 512 K kg mol - 1 ; the molality of solution and boiling point of solution respectively will be -

Step-by-step solution

Depression in freezing point is given as ΔT f = K f m Molality of solution m = ΔT f K f or m = 0 . 6 1 . 86 = 0 . 322   m Elevation in boiling point of solution is given as ΔT b = k b × m ΔT b = 0 . 512 × 0 . 322 ΔT b = 0 . 165 ∴ Boiling point of solution = 373 + 0 . 16 = 373 . 16   K