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BITSAT 2020
Exam
BITSAT
Year
2020
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

BITSAT 2020 · Chemistry · Some Basic Concepts of Chemistry

The amount of H_ 2 O_ 2 present in 1 litre of 1.5 N H_ 2 O_ 2...

The amount of H2O2\mathrm{H}_{2} \mathrm{O}_{2} present in 1 litre of 1.5NH2O21.5 \mathrm{ N} \mathrm{H}_{2} \mathrm{O}_{2} solution, is:

Options

  1. A25.5g25.5 \mathrm{ g}
  2. B3.0g3.0 \mathrm{ g}
  3. C8.0g8.0 \mathrm{ g}
  4. D2.5g2.5 \mathrm{ g}

Correct answer

A. 25.5g25.5 \mathrm{ g}

Step-by-step solution

Molecular weight of H2O2=34\mathrm{H}_{2} \mathrm{O}_{2}=34 Equivalent weight of H2O2=17∴1L\mathrm{H}_{2} \mathrm{O}_{2}=17\therefore 1 \mathrm{ L} of 1NH2O2has=17g1 \mathrm{ N} \mathrm{H}_{2} \mathrm{O}_{2} \mathrm{has}=17 \mathrm{ g} of H2O∴1\mathrm{H}_{2} \mathrm{O}\therefore 1 Lof 1.5NH2O21.5 \mathrm{NH}_{2} \mathrm{O}_{2} has =1.5×17=25.5gofH2O2=1.5 \times 17=25.5 \mathrm{ g} \mathrm{of} \mathrm{H}_{2} \mathrm{O}_{2}
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